NEC 2023 · NEC 2026 notes · updated November 7, 2026
Free Journeyman Electrician Practice Test (2026)
80 questions with answers explained and the NEC section for each one. No sign-up, no email: click an answer, read why, and get your score by section at the end.
Journeyman practice test · 80 questions0 / 80 answered–
Grounding & Bonding
Which color or marking may NOT be used to identify an insulated equipment grounding conductor?
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Correct answer: B. Equipment grounding conductors may be bare, green, or green with one or more yellow stripes. Gray, like white, is reserved for the grounded (neutral) conductor, so it can never identify an EGC.Reference: NEC 250.119; NEC 200.6
General & Definitions
Before touching conductors that have been switched off and locked out, what is the correct way to confirm they are de-energized?
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Correct answer: D. Establishing an electrically safe work condition requires verifying the absence of voltage with a properly rated test instrument, and proving the instrument works on a known source before and after the test. Panel labels are often wrong, and a non-contact pen alone is not considered adequate verification. Test before you touch.Reference: NFPA 70E, electrically safe work condition (verify absence of voltage)
Calculations
A balanced 3-phase load operates at 480 volts, drawing 50 A per phase at a power factor of 0.85. What is the true power?
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Correct answer: D. Three-phase true power = 1.732 x E x I x PF = 1.732 x 480 x 50 x 0.85, about 35,333 W, or 35.3 kW. Leaving out the power factor gives 41.6 kW, which is the apparent power in kVA. Leaving out 1.732 gives 20.4 kW, the single-phase mistake.Reference: Formula: P = 1.732 x E x I x PF
Electrical Theory
If the length of a copper conductor is doubled while its size stays the same, its resistance will:
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Correct answer: B. Conductor resistance is directly proportional to length and inversely proportional to cross-sectional area. Doubling the length doubles the resistance. Doubling the cross-sectional area, not the length, would cut it in half.Reference: R = K x L / CM (resistance proportional to length)
General & Definitions
Under a typical lockout/tagout program, who is normally allowed to remove a personal lock from an energy-isolating device?
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Correct answer: C. Each lock is personal and is removed by the person who installed it. Only a specific, documented employer procedure (with verification that the worker is not on site and has been informed) allows anyone else to remove it. Letting any crew member pull locks defeats the purpose of individual protection.Reference: NFPA 70E lockout/tagout principles; OSHA 29 CFR 1910.147 (general)
Calculations
A single-phase 240-volt load draws 40 A over a one-way distance of 150 ft using 8 AWG copper (16,510 circular mils). Using K = 12.9, what is the approximate voltage drop as a percentage of 240 V?
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Correct answer: A. VD = 2 x K x I x L / CM = 2 x 12.9 x 40 x 150 / 16,510, about 9.4 V, and 9.4 / 240 is about 3.9%. Dividing 9.4 V by 120 V instead gives 7.8%, the most common error. The NEC informational notes recommend about 3% for a branch circuit and 5% total.Reference: Formula: VD = 2KIL / CM; NEC Chapter 9, Table 8; NEC 210.19 Informational Note
Electrical Theory
In a purely capacitive AC circuit, how is the current related to the voltage?
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Correct answer: D. In an ideal capacitor, current leads voltage by 90°. In an ideal inductor, current lags voltage by 90°. The memory aid ELI the ICE man helps: in L, E comes before I; in C, I comes before E.Reference: AC theory: capacitive reactance and phase angle
Wiring & Protection
A 10 AWG copper THHN conductor has a 90°C ampacity of 40 A. For a general-purpose branch circuit, what is the largest overcurrent device that may protect it?
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Correct answer: D. 240.4(D) limits 10 AWG copper to 30 A of overcurrent protection regardless of the insulation rating. The 90°C ampacity is useful as a starting point for derating, but it does not raise the OCPD limit. Special cases such as motor and air-conditioning circuits follow their own articles.Reference: NEC 240.4(D); NEC 310.16
Calculations
A dwelling has one household range rated 14 kW. Using Column C of the range demand table and its note for ranges over 12 kW, what is the demand load?
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Correct answer: A. Column C gives 8 kW for one range up to 12 kW. For each kW over 12 kW, the Column C value increases by 5%: 14 kW is 2 kW over, so 8 x 1.10 = 8.8 kW. Stopping at 8 kW ignores the note for larger ranges. Load calculation rules are in Article 220 in NEC 2023; NEC 2026 moved them to Article 120.Reference: NEC 2023 220.55 and Table 220.55, Note 1 (Article 120 in NEC 2026)
Calculations
A metal box has a volume of 21.0 cu in. It will contain only 14 AWG insulated conductors, with no devices, clamps, fittings or grounding conductors. What is the maximum number of conductors allowed? (14 AWG = 2.00 cu in. per conductor)
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Correct answer: B. 21.0 / 2.00 = 10.5, and you always round down for box fill, so the maximum is 10 conductors. Rounding up to 11 would overfill the box. Box fill is never rounded up.Reference: NEC 314.16(A) and Table 314.16(B)
Wiring Methods & Materials
A conduit will contain exactly two conductors. What is the maximum percentage of the conduit's cross-sectional area those conductors may fill?
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Correct answer: B. Chapter 9, Table 1 allows 53% fill for one conductor, 31% for two conductors, and 40% for three or more. Two conductors get the lowest percentage because two round conductors tend to jam side by side during a pull. 40% is the tempting answer because it is the value used most often.Reference: NEC Chapter 9, Table 1
Calculations
A commercial lighting branch circuit supplies a continuous load of 24 A and no noncontinuous load. What is the minimum standard overcurrent device rating?
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Correct answer: A. The overcurrent device must be at least 125% of the continuous load: 24 x 1.25 = 30 A, and 30 A is a standard size. A 25 A device would be loaded beyond the 80% that continuous operation allows on a standard breaker.Reference: NEC 210.20(A); NEC 240.6(A)
Calculations
A 45-kVA, 3-phase transformer has a 480-volt primary and is protected on the primary side only. Using the basic 125% rule and the next-higher-standard-size allowance, what is the largest standard primary overcurrent device permitted?
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Correct answer: C. Primary current = 45,000 / (480 x 1.732), about 54.1 A. At 125% this is about 67.7 A; for currents of 9 A or more the next higher standard size is permitted, which is 70 A. 80 A would exceed the rule. The secondary conductors still need their own protection under the conductor rules.Reference: NEC 450.3(B) and Table 450.3(B); NEC 240.6(A); I = VA / (E x 1.732)
Electrical Theory
On a 3-phase, 4-wire wye system with only line-to-neutral resistive loads, phases A, B and C carry 50 A, 40 A and 30 A. What is the approximate neutral current?
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Correct answer: A. Neutral current = square root of (A² + B² + C² - AB - BC - CA) = square root of (2,500 + 1,600 + 900 - 2,000 - 1,200 - 1,500) = square root of 300, about 17.3 A. 20 A just subtracts the highest and lowest phases, which works only for single-phase 3-wire circuits.Reference: Formula: IN = sqrt(A² + B² + C² - AB - BC - CA)
Grounding & Bonding
What is the minimum size copper equipment grounding conductor for a circuit protected by a 60-A overcurrent device?
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Correct answer: C. Equipment grounding conductors are sized from the rating of the overcurrent device ahead of the circuit, and a 60-A device calls for 10 AWG copper. 8 AWG copper is the minimum for 100 A. The EGC is not sized from the circuit conductors themselves.Reference: NEC 250.122 and Table 250.122
Calculations
The same 25-hp, 460-volt, 3-phase motor (34 A table FLC) is protected by an inverse time circuit breaker. Using the basic percentage and the next-higher-standard-size allowance, what is the largest breaker permitted?
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Correct answer: A. An inverse time breaker may be set at up to 250% of the table FLC: 34 x 2.5 = 85 A. 85 A is not a standard size, so the next higher standard size, 90 A, is permitted. 85 A by itself is not a breaker rating you can buy, and 100 A would exceed the rule unless the motor cannot start and a further exception applies.Reference: NEC 430.52(C)(1) and its table; NEC 240.6(A)
Calculations
A device box contains two 12/2 NM cables with ground (each cable has two insulated conductors and one bare grounding conductor), one receptacle, and internal cable clamps. What is the minimum box volume required? (12 AWG = 2.25 cu in. per conductor)
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Correct answer: A. Count 4 insulated conductors, 1 for the equipment grounding conductors, 2 for the receptacle yoke and 1 for the internal clamps, for 8 volumes. 8 x 2.25 = 18.0 cu in. Counting each bare ground separately gives 20.25 cu in., but up to four equipment grounding conductors together count as a single volume (each one beyond four adds a quarter volume).Reference: NEC 314.16(B)(1), (B)(2), (B)(4), (B)(5) and Table 314.16(B)
General & Definitions
Operation of equipment above its normal full-load rating, or of a conductor above its ampacity, which would cause damage if it lasts long enough, is the NEC definition of:
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Correct answer: A. That is the Article 100 definition of overload, and the definition specifically excludes faults such as short circuits and ground faults. Overcurrent is the broader term that covers overloads, short circuits and ground faults together, which is why it is the most tempting wrong answer.Reference: NEC Article 100, Overload and Overcurrent
Calculations
A 4-in. square x 1 1/2-in. deep box (21.0 cu in.) will have three 12/2 NM cables with ground, one single-pole switch, and internal cable clamps. What is the minimum volume required, and does the box work? (12 AWG = 2.25 cu in.)
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Correct answer: C. Count 6 insulated conductors, 1 for all grounds, 2 for the switch yoke and 1 for the clamps: 10 x 2.25 = 22.5 cu in. That exceeds the 21.0 cu in. box, so a deeper box or an extension ring is needed. Forgetting the clamp allowance gives 20.25 cu in. and the wrong conclusion that the box is fine.Reference: NEC 314.16(B); NEC 314.16(A)
Electrical Theory
An ideal single-phase transformer steps 480 V down to 120 V. If the secondary current is 40 A, what is the primary current?
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Correct answer: A. The turns ratio is 480 / 120 = 4:1. Current changes in the opposite direction from voltage, so primary current = 40 / 4 = 10 A. 160 A comes from multiplying instead of dividing, which would create power out of nothing.Reference: Transformer ratio: Ep / Es = Is / Ip
Electrical Theory
A load draws 10 kW of true power and 12.5 kVA of apparent power. What is its power factor?
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Correct answer: D. Power factor = true power / apparent power = 10 / 12.5 = 0.80. Power factor can never be more than 1.0, which rules out 1.25 (the ratio inverted).Reference: Formula: PF = W / VA
Calculations
What is the full-load secondary current of a 75-kVA, 3-phase transformer with a 208Y/120-volt secondary?
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Correct answer: B. For a 3-phase transformer, I = VA / (E x 1.732) = 75,000 / (208 x 1.732), about 208 A. Dividing by 208 without the 1.732 gives about 360 A, the single-phase mistake. Dividing by 120 gives 625 A, which uses the wrong voltage.Reference: Formula: I = kVA x 1,000 / (E x 1.732)
Calculations
Using the optional method for a dwelling unit, the general loads total 30 kVA before demand factors. What is the demand load for these general loads?
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Correct answer: D. The optional method takes the first 10 kVA at 100% and the remainder at 40%: 10 + (20 x 0.40) = 18 kVA. Heating and air-conditioning loads are then added separately under their own rule. Taking 40% of the whole 30 kVA would give 12 kVA, which is wrong. Load calculation rules are in Article 220 in NEC 2023; NEC 2026 moved them to Article 120.Reference: NEC 2023 220.82(B) (Article 120 in NEC 2026)
Electrical Theory
A 6-ohm resistor and a 3-ohm resistor are connected in parallel. What is the total resistance?
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Correct answer: D. For two resistors in parallel, R = (R1 x R2) / (R1 + R2) = 18 / 9 = 2 ohms. The total of a parallel group is always less than the smallest branch. 9 ohms is the series total.Reference: Parallel resistance: R = (R1 x R2) / (R1 + R2)
General & Definitions
In the NEC, the term Approved means:
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Correct answer: B. Approved means acceptable to the authority having jurisdiction (AHJ), usually the electrical inspector. Listed is a different term: it means the product appears on a list published by an organization acceptable to the AHJ. A product can be listed and still not be approved for a particular use.Reference: NEC Article 100, Approved; NEC 110.2
Electrical Theory
On a 120/240-volt, 3-phase, 4-wire delta system (center-tapped on one winding), what is the approximate voltage from the high leg to the neutral?
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Correct answer: B. The high leg to neutral voltage is about 120 x 1.732, which is roughly 208 V. This conductor must be marked orange (or another effective means) and, in panelboards, connected to the B phase. Connecting a 120-volt load to it would damage the load.Reference: Delta high-leg voltage = 1.732 x 120 V; NEC 110.15; NEC 408.3(E)(1)
Wiring & Protection
What is the minimum number and rating of small-appliance branch circuits required for the kitchen countertop receptacles in a dwelling unit?
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Correct answer: A. Dwellings require at least two 20 A small-appliance branch circuits for the kitchen, pantry, dining room and similar receptacle outlets, and the countertop receptacles must be served by at least two of them. 15 A circuits are not allowed for this purpose.Reference: NEC 210.11(C)(1); NEC 210.52(B)
Wiring & Protection
What is the minimum vertical clearance for service-drop conductors over a public street or alley subject to truck traffic?
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Correct answer: A. Service-drop conductors over public streets, alleys, roads and parking areas subject to truck traffic need at least 18 ft of clearance. Lower clearances apply over residential driveways and areas such as sidewalks where trucks are not expected.Reference: NEC 230.24(B)
Calculations
In a dwelling load calculation using the standard method, a household clothes dryer nameplate reads 4,500 W. What load must be used for the dryer?
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Correct answer: C. The dryer load is 5,000 W or the nameplate rating, whichever is larger. Since 4,500 W is less than 5,000 W, you must use 5,000 W. Using the nameplate value alone understates the load. Load calculation rules are in Article 220 in NEC 2023; NEC 2026 moved them to Article 120.Reference: NEC 2023 220.54 (Article 120 in NEC 2026)
General & Definitions
As defined in the NEC, a branch circuit consists of which conductors?
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Correct answer: A. A branch circuit starts at the last overcurrent device and ends at the outlets it serves. Conductors that run from the service equipment to the final branch-circuit overcurrent device are feeders, which is the most common mix-up. In NEC 2023 all definitions are consolidated in Article 100.Reference: NEC Article 100, Branch Circuit and Feeder
Calculations
A 25-hp, 460-volt, 3-phase induction motor has a table full-load current of 34 A. What is the minimum ampacity of its branch-circuit conductors?
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Correct answer: D. Single-motor branch-circuit conductors must have an ampacity of at least 125% of the table full-load current: 34 x 1.25 = 42.5 A. 39.1 A uses 115%, which belongs to some overload settings, not conductors. The full-load current comes from Table 430.250, not the nameplate.Reference: NEC 430.22; NEC 430.6(A)(1); Table 430.250
Equipment & Motors
A switchboard on a 480Y/277-volt system has exposed live parts on both sides of the working space (Condition 3). What is the minimum depth of the working space?
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Correct answer: C. A 480Y/277-volt system is 277 V to ground, which falls in the 151-600 V row of the working space table. Condition 3 in that row requires 4 ft. Condition 2 (live parts on one side, grounded parts on the other) would require 3 1/2 ft, which is the most common wrong answer.Reference: NEC 110.26(A)(1) and Table 110.26(A)(1)
Wiring Methods & Materials
In a residential yard, what is the minimum cover for a 120-volt, 20-ampere branch circuit that has GFCI protection and overcurrent protection of 20 A or less?
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Correct answer: A. Table 300.5(A) allows 12 in. of cover for residential branch circuits rated 120 V or less that have GFCI protection and overcurrent protection of 20 A or less. Without all of those conditions, direct-buried UF cable would need 24 in. This reduced depth is a favorite exam question because every condition must be met at the same time.Reference: NEC 300.5(A) and Table 300.5(A), Column 4 (NEC 2023)
Grounding & Bonding
The portion of a grounding electrode conductor that connects only to a concrete-encased electrode is not required to be larger than:
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Correct answer: A. When the grounding electrode conductor serves only a concrete-encased electrode, it does not need to be larger than 4 AWG copper. Do not confuse this with the 6 AWG copper limit that applies to rod, pipe and plate electrodes.Reference: NEC 250.66(B)
General & Definitions
Which installation would make a panelboard NOT readily accessible as defined by the NEC?
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Correct answer: C. Readily accessible means equipment can be reached quickly for operation or inspection without climbing over or removing obstacles, or resorting to portable ladders. Needing a ladder automatically disqualifies the location. An ordinary unlocked door does not prevent ready access.Reference: NEC Article 100, Accessible, Readily (Readily Accessible)
Wiring & Protection
In a dwelling unit, which location is NOT permitted for branch-circuit overcurrent devices (other than supplementary protection)?
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Correct answer: C. Overcurrent devices may not be located in bathrooms of dwelling units, dormitory units, or guest rooms and guest suites. They also may not be placed near easily ignitible material such as in clothes closets. Garages, basements and laundry rooms are common and acceptable panel locations.Reference: NEC 240.24(E); NEC 240.24(D)
Electrical Theory
Why will a standard transformer not work properly when its primary is connected to a steady DC source?
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Correct answer: D. Transformers work by mutual induction, which needs a changing magnetic flux. Steady DC creates a constant flux, so nothing is induced in the secondary, and only the low winding resistance limits primary current, which can overheat the winding. DC does not reverse polarity at all.Reference: Transformer theory: mutual induction requires changing flux
General & Definitions
In NFPA 70E, the limited approach boundary and the restricted approach boundary protect workers mainly from which hazard?
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Correct answer: D. The limited and restricted approach boundaries are shock protection boundaries based on distance from exposed energized parts. The arc flash boundary is a separate boundary based on incident energy. Mixing the two up is a common exam trap.Reference: NFPA 70E, approach boundaries (shock risk assessment)
Special Occupancies & Conditions
What is the minimum conductor required for the equipotential bonding grid of a permanently installed swimming pool when a conductor is used?
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Correct answer: A. Equipotential bonding conductors for pools must be solid copper, 8 AWG or larger. The goal is to keep all metal parts around the pool at the same voltage, not to clear faults, so these conductors are not required to be run back to the panel.Reference: NEC 680.26(B)
Calculations
A 120-volt branch circuit carries 16 A over a one-way distance of 100 ft. Voltage drop must be limited to 3% (3.6 V). Using K = 12.9 for copper, what is the smallest conductor that works? (12 AWG = 6,530 cmil; 10 AWG = 10,380 cmil; 8 AWG = 16,510 cmil; 6 AWG = 26,240 cmil)
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Correct answer: D. Required CM = 2 x K x I x L / VD = 2 x 12.9 x 16 x 100 / 3.6, about 11,467 cmil. 10 AWG at 10,380 cmil is just short, so 8 AWG at 16,510 cmil is the smallest size that meets the 3% target. 10 AWG is tempting because it is close, but it would exceed the allowed drop.Reference: Formula: CM = 2KIL / VD; NEC Chapter 9, Table 8
Wiring & Protection
In a dwelling bathroom, at least one receptacle outlet must be installed within what distance of the outside edge of each basin?
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Correct answer: D. At least one receptacle must be within 3 ft of the outside edge of each basin, and it must be on a wall or partition next to the basin or on the side or face of the vanity within the permitted distance below the countertop. 6 ft is tempting because of the GFCI sink rule, but that rule decides protection, not placement.Reference: NEC 210.52(D)
Wiring Methods & Materials
Type NM cable run along framing must be secured within 12 in. of each box and supported at intervals not exceeding:
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Correct answer: D. NM cable must be secured within 12 in. of every box or fitting and at intervals of no more than 4 1/2 ft. The 10 ft interval belongs to EMT and rigid conduit, which are far stiffer than cable.Reference: NEC 334.30
Wiring Methods & Materials
EMT must be securely fastened within what distance of each outlet box, junction box or other termination?
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Correct answer: A. EMT must be fastened within 3 ft of each box or termination and supported at intervals not exceeding 10 ft. 12 in. is the securing distance for NM cable, not for EMT.Reference: NEC 358.30
General & Definitions
In NFPA 70E, the arc flash boundary is the distance from an arc source at which the incident energy equals:
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Correct answer: C. The arc flash boundary is set where incident energy drops to 1.2 cal/cm², the level associated with the onset of a second-degree burn on bare skin. Values like 4 or 8 cal/cm² relate to PPE ratings, not to where the boundary is drawn. Anyone crossing this boundary needs arc-rated protection.Reference: NFPA 70E, Article 100 (Arc Flash Boundary)
Wiring & Protection
A 12 AWG THHN copper conductor lands on a 20-A breaker whose terminals are not marked with a temperature rating. Which ampacity column must be used for the conductor's final ampacity at the termination?
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Correct answer: D. For circuits rated 100 A or less, or conductors 14 AWG through 1 AWG, terminations are assumed to be 60°C unless the equipment is listed and marked for a higher rating. The 90°C rating of THHN can be used as the starting point for derating, but the final value cannot exceed the termination rating.Reference: NEC 110.14(C)(1)(a)
General & Definitions
Which statement best matches the NEC definition of a qualified person?
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Correct answer: B. The NEC defines a qualified person by skills, knowledge and safety training related to the specific equipment and its hazards, not by a license or years of experience. A licensed electrician may still be unqualified for a task they are not trained for. NFPA 70E uses the same concept.Reference: NEC Article 100, Qualified Person; NFPA 70E (definitions)
Electrical Theory
A resistive heater is designed for 240 V. If it is connected to 120 V instead, its power output will be approximately:
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Correct answer: B. Power in a resistive load is P = E² / R. With the same resistance, half the voltage gives (1/2)² = one-quarter of the power. One-half is the tempting answer if you forget that current also drops by half.Reference: Formula: P = E² / R
Wiring Methods & Materials
In general locations (not under a building, slab or driveway), what is the minimum cover for direct-buried UF cable on a 120/240-volt circuit?
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Correct answer: A. Direct-burial cables require 24 in. of cover in general locations. 18 in. is the depth for nonmetallic raceways such as PVC, and 6 in. applies to rigid metal or intermediate metal conduit. Reduced depths apply only to specific situations listed in the table.Reference: NEC 300.5(A) and Table 300.5(A) (NEC 2023)
Calculations
A 3-phase, 208-volt load draws 60 A over a one-way distance of 200 ft on 4 AWG copper (41,740 cmil). Using K = 12.9, what is the approximate voltage drop?
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Correct answer: B. For 3-phase circuits, VD = 1.732 x K x I x L / CM = 1.732 x 12.9 x 60 x 200 / 41,740, about 6.4 V (roughly 3.1% of 208 V). Using the single-phase multiplier of 2 instead of 1.732 gives 7.4 V, which is the tempting wrong answer.Reference: Formula: VD = 1.732KIL / CM; NEC Chapter 9, Table 8
Grounding & Bonding
A single ground rod is installed as the grounding electrode and is not shown to have a resistance to earth of 25 ohms or less. What does the NEC require?
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Correct answer: C. A single rod must be supplemented by another electrode unless it is shown to have 25 ohms or less to earth. When the supplemental electrode is another rod, the two must be at least 6 ft apart so their zones of influence do not overlap too much. Most installers simply drive two rods instead of testing.Reference: NEC 250.53(A)(2) and (A)(3)
Calculations
A 3/4-in. EMT has a total internal area of 0.533 sq in., and 40% of that is 0.213 sq in. A 12 AWG THHN conductor has an area of 0.0133 sq in. How many 12 AWG THHN conductors may be installed?
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Correct answer: A. With more than two conductors the 40% fill applies: 0.213 / 0.0133 is about 16 conductors. Dividing the full 0.533 sq in. area by 0.0133 gives 40, which ignores the fill limit. In real practice these values come from Chapter 9, Tables 4 and 5.Reference: NEC Chapter 9, Table 1, Table 4 and Table 5
Grounding & Bonding
When a grounding electrode conductor runs only to a ground rod and does not extend to any other type of electrode, it is not required to be larger than:
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Correct answer: B. The portion of a grounding electrode conductor that serves only a rod, pipe or plate electrode does not need to be larger than 6 AWG copper (or 4 AWG aluminum), whatever the service size. A rod cannot carry more fault current into the earth than this conductor size can handle, so a bigger conductor adds nothing.Reference: NEC 250.66(A)
Wiring & Protection
For a dwelling kitchen wall countertop, receptacles must be installed so that no point along the wall line is more than what distance from a receptacle outlet?
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Correct answer: D. Countertop receptacles must be placed so no point along the wall line is more than 24 in. from a receptacle, which typically gives a maximum spacing of 4 ft. Countertop spaces 12 in. or wider also need a receptacle, which is why 12 in. is a tempting but wrong answer here.Reference: NEC 210.52(C)(1)
Grounding & Bonding
A metal underground water pipe can serve as a grounding electrode when it is in direct contact with the earth for at least:
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Correct answer: B. The pipe must be in direct contact with the earth for 10 ft or more. Even then, it must be supplemented by an additional electrode, because water piping can be replaced with plastic later. 8 ft is tempting because it is the rod length requirement.Reference: NEC 250.52(A)(1); NEC 250.53(D)(2)
Electrical Theory
On a 120/240-volt single-phase 3-wire circuit, line 1 carries 30 A and line 2 carries 20 A (all loads are line-to-neutral). What current flows on the neutral?
Show answer & explanation
Correct answer: B. On a single-phase 3-wire system, the neutral carries the difference between the two line currents: 30 - 20 = 10 A. Adding them (50 A) is the most common mistake. The neutral would carry zero only if the two loads were exactly balanced.Reference: Single-phase 3-wire neutral current = I1 - I2
Wiring & Protection
A 120/240-volt multiwire branch circuit shares one neutral between two ungrounded conductors. Which requirement applies at the point where the circuit originates?
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Correct answer: C. A multiwire branch circuit must have a means at its point of origin that disconnects all ungrounded conductors at the same time, such as a 2-pole breaker or listed handle ties. This keeps someone from opening one breaker and then working on a shared neutral that is still carrying current. The neutral is never fused separately.Reference: NEC 210.4(B)
Calculations
A dwelling has 2,000 sq ft of living area, two small-appliance branch circuits and one laundry circuit. Using the standard method, what is the demand load for general lighting plus small-appliance and laundry circuits (3 VA per sq ft; 1,500 VA per small-appliance and laundry circuit; first 3,000 VA at 100% and the next portion at 35%)?
Show answer & explanation
Correct answer: B. Total = 2,000 x 3 + 2 x 1,500 + 1,500 = 10,500 VA. Apply the demand factors: 3,000 VA at 100% plus 7,500 VA at 35% (2,625 VA) = 5,625 VA. 10,500 VA forgets the demand factors altogether. These are NEC 2023 values; NEC 2026 moves load calculations to Article 120 and lowers the dwelling unit load from 3 to 2 VA per sq ft.Reference: NEC 2023 220.41, 220.52(A) and (B), Table 220.45 (in NEC 2026 these move to Article 120, and the dwelling unit load becomes 2 VA per sq ft)
Special Occupancies & Conditions
A hazardous (classified) location where combustible dust may be present is designated as:
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Correct answer: B. Class II locations involve combustible dust, such as grain elevators or flour mills. Class I covers flammable gases, vapors or liquids, and Class III covers ignitible fibers or flyings. There is no Class IV in the NEC classification system.Reference: NEC 500.5(C)
Calculations
What is the full-load secondary current of a 25-kVA single-phase transformer with a 240-volt secondary?
Show answer & explanation
Correct answer: D. For a single-phase transformer, I = VA / E = 25,000 / 240, about 104.2 A. Using 120 V would give 208 A, but the full 240-volt winding carries the rated load in a 120/240-volt secondary. No 1.732 factor applies to single-phase.Reference: Formula: I = kVA x 1,000 / E
Calculations
A feeder supplies three 460-volt, 3-phase motors with table full-load currents of 34 A, 14 A and 14 A. What is the minimum feeder conductor ampacity?
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Correct answer: C. Feeder conductors must carry 125% of the largest motor FLC plus the sum of the others: 34 x 1.25 + 14 + 14 = 42.5 + 28 = 70.5 A. Multiplying the whole 62 A total by 125% gives 77.5 A, which oversizes the feeder. Only the largest motor gets the extra 25%.Reference: NEC 430.24
Calculations
A straight pull is made through a pull box using 3-in. trade size conduits (the largest raceway entering). What is the minimum length of the box?
Show answer & explanation
Correct answer: C. For straight pulls with conductors 4 AWG or larger, the box length must be at least 8 times the trade size of the largest raceway: 8 x 3 = 24 in. 18 in. comes from the angle-pull multiplier of 6, which is the most common mix-up.Reference: NEC 314.28(A)(1)
Electrical Theory
In a series circuit, which quantity is the same through every component?
Show answer & explanation
Correct answer: C. A series circuit has only one path, so the same current flows through every component. Voltage divides across the components in proportion to their resistance. In a parallel circuit it is the voltage that is the same across every branch.Reference: Series circuit rules; Kirchhoff's current law
Electrical Theory
On a 3-phase, 4-wire wye system, the line-to-neutral voltage is 277 V. What is the line-to-line voltage?
Show answer & explanation
Correct answer: D. In a wye system, line-to-line voltage = line-to-neutral voltage x 1.732: 277 x 1.732 is about 480 V. 554 V results from doubling, which applies only to the two ends of a single-phase center-tapped winding.Reference: Wye system: E(L-L) = 1.732 x E(L-N)
Wiring & Protection
In a dwelling unit, which of these locations requires GFCI protection for 125-volt, 15- and 20-ampere receptacles?
Show answer & explanation
Correct answer: D. Dwelling garages (and accessory buildings with a floor at or below grade not intended as habitable rooms) are on the 210.8(A) GFCI list. Bedrooms, living rooms and hallways are not on that list on their own; they need AFCI protection under 210.12 instead, which is a different device requirement.Reference: NEC 210.8(A)
Wiring Methods & Materials
Between pull points (such as boxes or conduit bodies), a conduit run may not contain more than the equivalent of how many degrees of bends in total?
Show answer & explanation
Correct answer: C. Raceway articles limit the total bends between pull points to 360°, the equivalent of four quarter bends. Beyond that, pulling tension can damage the insulation. Offsets and kicks count toward the total, which candidates often forget.Reference: NEC 358.26 (EMT); same rule in 344.26, 352.26 and other raceway articles
Wiring & Protection
In a dwelling unit, which area does NOT require AFCI protection for 120-volt, 15- and 20-ampere branch circuits under NEC 2023?
Show answer & explanation
Correct answer: A. Bathrooms are not on the 210.12(A) AFCI list; they are covered by GFCI requirements instead. Bedrooms, hallways and laundry areas are all listed, along with kitchens, family rooms, dining rooms, living rooms, closets and similar areas. Laundry areas surprise many candidates because they also require GFCI.Reference: NEC 210.12(A)
Wiring & Protection
Unless specifically permitted elsewhere in the Code (for example, motor circuits), what is the maximum overcurrent protection for 12 AWG copper conductors?
Show answer & explanation
Correct answer: C. The small-conductor rule limits 12 AWG copper to a 20 A overcurrent device. Table 310.16 lists 12 AWG copper at 25 A in the 75°C column, which is why 25 A is tempting, but 240.4(D) caps the protection at 20 A.Reference: NEC 240.4(D)
General & Definitions
Under the NEC, a continuous load is one where the maximum current is expected to continue for at least how long?
Show answer & explanation
Correct answer: C. Article 100 defines a continuous load as one whose maximum current is expected to last 3 hours or more. This matters because branch circuits and feeders serving continuous loads must be sized at 125% of the continuous portion. Eight hours is a common wrong guess borrowed from work-shift thinking, but it is not the NEC threshold.Reference: NEC Article 100, Continuous Load; NEC 210.19, 210.20(A)
Special Occupancies & Conditions
At a dwelling with a permanently installed pool, at least one 125-volt, 15- or 20-ampere general-purpose receptacle must be installed at what distance from the inside wall of the pool?
Show answer & explanation
Correct answer: D. Article 680 requires at least one general-purpose receptacle between 6 ft and 20 ft from the inside wall of a permanently installed dwelling pool. This gives people a nearby legal outlet so they do not run extension cords. Receptacles within 20 ft of the pool also require GFCI protection.Reference: NEC 680.22(A)(1); NEC 680.22(A)(4)
Calculations
A motor has a nameplate full-load current of 30 A and a marked service factor of 1.15. What is the maximum rating of a separate overload device under the basic rule?
Show answer & explanation
Correct answer: C. A motor with a service factor of 1.15 or more may have overload protection up to 125% of nameplate current: 30 x 1.25 = 37.5 A. 34.5 A uses 115%, which applies only to motors without the 1.15 service factor or 40°C rise marking. Overloads are based on nameplate current, not table values.Reference: NEC 430.32(A)(1)
Calculations
A 4,500-watt, 240-volt storage water heater (120 gallons or less) is installed in a dwelling. What is the minimum branch-circuit ampacity based on the load?
Show answer & explanation
Correct answer: D. The load is 4,500 / 240 = 18.75 A. Storage water heaters of 120 gallons or less are treated as continuous loads, so the branch circuit must be at least 125%: 18.75 x 1.25, about 23.4 A. 18.75 A forgets the 125% factor.Reference: NEC 422.13; NEC 422.10(A); I = P / E
Electrical Theory
What is the inductive reactance of a 0.1-henry inductor on a 60-Hz system?
Show answer & explanation
Correct answer: A. XL = 2 x pi x f x L = 2 x 3.1416 x 60 x 0.1, about 37.7 ohms. 377 ohms results from forgetting the 0.1 multiplier, and 0.0265 is the reciprocal. Inductive reactance rises as frequency rises.Reference: Formula: XL = 2 x pi x f x L
Calculations
An angle pull is made in a pull box. One wall has a row of three raceways entering: one 3-in., and two 2-in. trade size (conductors 4 AWG and larger). What is the minimum distance from that wall to the opposite wall?
Show answer & explanation
Correct answer: B. For angle or U pulls, the distance is 6 times the largest raceway plus the sum of the other raceways in the same row on the same wall: 6 x 3 + 2 + 2 = 22 in. Using only 6 x 3 = 18 in. forgets the additional raceways, and 24 in. wrongly uses the straight-pull rule.Reference: NEC 314.28(A)(2)
Electrical Theory
A sine-wave voltage has a peak value of 170 volts. What is its approximate RMS (effective) value?
Show answer & explanation
Correct answer: C. RMS = peak x 0.707, so 170 x 0.707 is about 120 V. This is why a nominal 120-volt system peaks near 170 V. 340 V is the peak-to-peak value, and 85 V is simply half the peak.Reference: Formula: E(rms) = 0.707 x E(peak)
Grounding & Bonding
At a feeder-supplied panelboard located in the same building as the service, how must the grounded (neutral) conductor be treated?
Show answer & explanation
Correct answer: B. The neutral-to-ground bond is made only at the service (or at a separately derived system). Downstream of the service disconnect, the neutral must stay isolated so normal neutral current does not flow on equipment grounding paths and metal enclosures. Installing a bonding screw in a subpanel is one of the most common field errors.Reference: NEC 250.24(A)(5); NEC 250.142(B)
Wiring & Protection
In a dwelling unit, receptacles located within what distance of the top inside edge of a sink bowl require GFCI protection?
Show answer & explanation
Correct answer: B. Receptacles within 6 ft of the top inside edge of a sink bowl need GFCI protection, measured as the shortest path a cord would follow. 3 ft is tempting because it is the bathroom basin receptacle placement distance in 210.52(D), a different rule.Reference: NEC 210.8(A)
Electrical Theory
A resistive load of 15 ohms is connected to 120 volts. What current flows?
Show answer & explanation
Correct answer: B. Ohm's law: I = E / R = 120 / 15 = 8 A. Multiplying (120 x 15 = 1,800) or dividing the wrong way (15 / 120 = 0.125) are the typical mistakes.Reference: Ohm's law: I = E / R
Calculations
A dwelling has four fastened-in-place appliances (not cooking equipment, dryers, space heating, A/C or EVSE): dishwasher 1,200 VA, disposal 900 VA, water heater 4,500 VA, and well pump 1,500 VA. What is their demand load using the standard method?
Show answer & explanation
Correct answer: C. When there are four or more qualifying fastened-in-place appliances on the same feeder or service, a 75% demand factor may be applied to their total: 8,100 x 0.75 = 6,075 VA. 8,100 VA is the total without the demand factor, which applies only when there are fewer than four such appliances. Fastened-in-place cooking equipment, dryers, space heating, air conditioning and EVSE do not count toward the four. Load calculation rules are in Article 220 in NEC 2023; NEC 2026 moved them to Article 120.Reference: NEC 2023 220.53 (Article 120 in NEC 2026)
Calculations
A 1,500-watt portable heater operates at 120 volts. How much current does it draw?
Show answer & explanation
Correct answer: A. Current equals power divided by voltage: 1,500 W / 120 V = 12.5 A. Answering 15 A confuses the load with the typical circuit rating. Because a heater is resistive, power factor is 1 and no correction is needed.Reference: Formula: I = P / E
Wiring & Protection
In a dwelling living room, general-purpose receptacles must be placed so that no point measured horizontally along the floor line of any wall space is more than how far from a receptacle?
Show answer & explanation
Correct answer: B. The rule is that no point along the wall line may be more than 6 ft from a receptacle, which is why receptacles end up roughly 12 ft apart. Candidates often answer 12 ft because they remember the spacing rather than the actual 6 ft measurement.Reference: NEC 210.52(A)(1)
0%
Your score by section. Answers you skipped count as wrong.
Sections in this test:
General & Definitions: 10
Wiring & Protection: 13
Grounding & Bonding: 7
Wiring Methods & Materials: 6
Equipment & Motors: 1
Special Occupancies & Conditions: 3
Calculations: 25
Electrical Theory: 15
How to pass the journeyman electrician exam
Journeyman exams test two things: finding the right rule in the NEC quickly, and doing the calculations without mistakes. Most candidates who fail know the trade — they run out of time looking things up or slip on a load calculation.
1. Know your state's exam
Number of questions, time, open or closed book, NEC edition and pass mark all change by state. Start from your state's official candidate bulletin: we summarize Texas, California and Florida with links to the official pages.
2. Learn the Code's layout, not its pages
Chapters 1–4 apply everywhere (general rules, wiring and protection, wiring methods, equipment); Chapters 5–7 modify them for special occupancies, equipment and conditions; Chapter 9 holds the tables for conduit fill and conductor properties. Tab your Code by article if your state allows it, and practice with the index: on an open-book exam the index is the fastest way in.
3. Drill the calculations every day
Ohm's law, power, voltage drop, box fill, conduit fill, motor circuits and dwelling load calculations make up a big share of most exams. Our calculations guide shows the formulas and worked examples.
4. Mind the NEC edition
If your state is on NEC 2026, remember that the load calculation rules moved from Article 220 to the new Article 120. Section numbers you memorized from older editions may have changed.
Practice by NEC article
NEC Article 110 — approval, workmanship, markings, working space and dedicated equipment space
NEC Article 210 — branch-circuit ratings, GFCI and AFCI protection and required receptacle outlets
NEC Article 240 — sizing and locating fuses and breakers, small-conductor rules and next-size-up
NEC Article 250 — system grounding, electrodes, bonding jumpers and equipment grounding conductors
NEC Articles 300 & 310 — cover depths, protection of cables, conductor ampacity and adjustment
NEC Article 314 — box fill counts and volumes, box support and accessibility
NEC Article 430 — motor full-load currents, conductor sizing, overloads and short-circuit protection
5. Time yourself
Use the timer on this test: 2 minutes per question is a useful pace for practice. Answer every question; skip the long lookups and come back to them.
We cite NEC section numbers only. The NEC's text is copyrighted by NFPA: read the actual rules in your own Code book or NFPA's free online access.
Get new questions and our journeyman guide first
We add new practice questions and state pages every month, and Prep Master Digital is preparing a complete Journeyman Electrician study guide with full-length tests and an audiobook. Leave your email and we will tell you when they are out.
Journeyman exam questions
How many questions are on the journeyman electrician exam?
It depends on the state. Texas (PSI) splits the exam into a knowledge part and a calculations part; California's general electrician exam has 100 questions. See our Texas, California and Florida pages, checked on official sources.
Which NEC edition is on my exam?
The edition your state or local jurisdiction has adopted for licensing exams — currently NEC 2020, 2023 or 2026 depending on the state. This test is based on NEC 2023 and flags the NEC 2026 changes that matter, like load calculations moving from Article 220 to Article 120.
Is the journeyman exam open book?
In many states yes: Texas lets you bring your own soft-bound NEC, for example, while California provides the Code on screen. Check your state's candidate bulletin; open book still means you must find answers fast, so practice with your Code.
What score do I need to pass?
It depends on the state: Texas and California require 70% (Texas on each of its two parts), Michigan and Florida's contractor exam 75%. Always check your state's candidate bulletin.
Are these real exam questions?
No. Every question here is written by our team and checked by a second reviewer. Real exam questions are confidential; anyone selling 'real exam questions' is breaking exam rules.
Do I need to sign up to see my score?
No. No account, no email: answer the questions and your score by section appears at the end. Email is optional, only if you want updates.
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